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Answer 1

Answer:

let the side AC be hypotenuse of trinagle ∆ ABC

let the side BC be base of triangle of ∆ ABC

given : side AC = 17 and side BC = 10.5

Applying Pythagoras theorem

Hyp² = base² + height²

(17)² = (10.5)² + (height)²

289 = 110.25 + height²

height² = 289 - 110.25

= 178.75

taking √ both side

height² = √178.75

height = 13.36

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