Question

answer it on a sheet of paper plz plz plZ
$( \frac{2}{9} ) {}^{3} \times (\frac{2}{9} ) {}^{ - 5}$
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Answer 1

$\huge\mathcal{Answer:}$

If x is a rational number and a,b are rational exponents, then

${x}^{a} \times {x}^{b} = x ^{a + b}$

Here,

Let's consider 2/9 as x and power as a and b

Then,

$(\frac{2}{9} ) ^{3} \times (\frac{2}{9} ) ^{ - 5}$

$(\frac{2}{9} ) ^{3 + ( - 5)}$

Always remember + × - = -

$( \frac{2}{9} ) ^{3 - 5}$

$(\frac{2}{9} )^{ - 2}$

If exponent is negative then we reciprocal the number

$(\frac{9}{2} )^{2} \: \: \: or \: \: \frac{81}{4}$

For be more clear refer to attachment

Answer 2

Here is your answer!!

Thanks!