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x=4 (Remainder Theorem)
k*4^3+3*4^2-3=2*4^3-5*4+k. (Because they’re remainders are equal)
64k+48-3=128-20+k
64k-k=128-20-48+3
63k=63
K=1
Option no.1
There you go
Pls mark brainlyest if you’re satisfied with my answer
k*4^3+3*4^2-3=2*4^3-5*4+k. (Because they’re remainders are equal)
64k+48-3=128-20+k
64k-k=128-20-48+3
63k=63
K=1
Option no.1
There you go
Pls mark brainlyest if you’re satisfied with my answer
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