Question

Answer it please......!! :D

Answer 1

Hello Aisworya

X³ + 3X²Y + 3XY² + Y³ - 8

WE CAN USE IDENTITY HERE OF ( X + Y ) ³ = [ X³ + 3X²Y + 3XY² + Y³ ]

SO ....

= [ X + Y ] ³ - 2³

WE CAN USE IDENTITY OF ( X³ - Y³ ) = ( X - Y ) ( X² + 2XY + Y² )

SO....

= [ [ X + Y ] - 2 ] × [ [ X + Y ]² + 2 [ X + Y ] × 2 + 2²

= ( X + Y - 2 ) ( X² + Y² + 2XY + 4XY + 4 )

= ( X + Y - 2 ) ( X² + Y² + 6XY + 4 )

HOPE IT HELPS

Answer 2

HELLO DEAR,



( x³+3x²y+3xy²+y³)-8

(x+y)³-8

{(x+y)³-(2)³}


we know ,
( a³ – b³) = (a – b)(a³ + ab + b³). 


(x+y-2){(x+y)³+(x+y)×2+2³)}

I HOPE ITS HELP YOU DEAR

THANKS