Question

answer it please help ​

Answer 1

Good question,

Here is your answer!

Find the lcm of denominator,

It will be (x-1)(x-2)(x-3)

=) [(x-3) + (x-1)]/[(x-1)(x-2)(x-3)] = 2/3

=) (2x-4)/[(x-1)(x-2)(x-3)] = 2/3

=) 2(x-2)/[(x-1)(x-2)(x-3)] = 2/3

=) 2/(x-1)(x-3) = 2/3

=) 3 = (x-1)(x-3)

=) 3 = x² - 4x + 3

=) 4x = x²

Hence x = 0 or 4.

Answer 2

hi mate

here is your answer

PLZ refer to the attachment

hope it helps

BE BRAINLY