Question

answer it please help mr​

Answer 1

Acc. to Question -

First km = 8rs

Subsequent distance = 5rs/km

Given: Distance covered = x

Total fare = y

So the linear equation goes this way -

=> y = 5(x-1) + 8

=> y = 5x - 5 + 8

=> y = 5x + 3

Hence , y = 5x + 3

When x = 0, y = 3

When x = 1, y = 5+3 = 8

When x = 2 , y = 10+3 = 13

Now We Prepare Table Of X and Y

$</p><p> <table border="1" ></p><p> </p><p> <tr></p><p> <td><b>x</b></td></p><p> <td>0</td></p><p> <td>1</td></p><p> <td>2</td></p><p> </tr></p><p> <tr></p><p> <td><b>y</b></td></p><p> <td>3</td></p><p> <td>8</td></p><p> <td>13</td></p><p> </tr></p><p></p><p> </table></p><p> </p><p> <b><i><u>Graph is in the attached image</u></i><b></p><p>$