Question

answer it please how to do it

Answer 1

Let the unit digit be x and tens digit be y.

Number = 10y+x

Given,

y=x+2

y-x=2                      Eq1

(y-x)=1/32*(10y+x)

32(y-x)=10y+x

32*2=10y+x

64=10y+x             Eq2

Adding 1 and 2,

y-x+10y+x = 2+64

11y=66

y=6

Substituting value of y in Eq1

y-x=2

6-x=2

x=4

Number = 10y+x = 64

Answer 2

Solution:
x=6,y=4
Number= 10x+y=10×6+4=60+4=64