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Answers
Answer:
Explanation:
first write reaction which is given
fe+2+kmno4 = mn+2 + fe+3
zn + fe+3 = fe+2 +zn+2
fe+2 +kmno4 = fe+3 +mn+2
in first reaction equivalent of kmno4 = equivalent of fe+2 = equivalent of fe+3
equivalent = f*moles = molarity*volume*f
equivalent of kmno4 =0.0028*50*5
=0.7
here equivalent of kmno4= equivalent of fe+2 = moles*1000*f
0.7=1000*moles
moles = 0.0007
and moles of fe+3 is also same as fe+2
in second reaction
zn+fe+3 = fe+2 +zn+2
fe+2 + kmno4 = mn+2 + fe+3
in above common ion is fe+2
check fe+2 valency factor in zn reaction and kmno4 reaction
if the valency factors of both reactions are same then equivalents are same in reactions
if not same equate moles as same of fe+2
valency factor of fe+2 in zn reaction = 1
valency factor of fe+ 2 in kmno4 reaction =1
as valency factors are same equate equivalent
equivalent of kmno4 = equivalent of fe+2 = equivalent of fe+3
m*v*f = moles * f = moles *f*1000
moles of fe+2 and fe+3 = 0.0028*48*5*10^-3
moles of fe+2 and fe+3 = 0.672*10^-3
concentration of fe+2/fe+3 in reaction with zn metal = 0.672*10^-3
concentration of fe+2/fe+3 in reaction with kmno4 in first = 0.7*10^-3