Question

answer it please plzzzzzzzzz please please plzzzzzzzzz​

Answer 1

mark me as brain list

Sol: D is the midpoint of BC. ⇒ AD = CD. Angle B is a right angled triangle. Consider ΔABC AC2 = AB2 + BC2 [Pythagoras theorem] ⇒ AC2 = AB2 + (2BD)2 ⇒ AC2 = AB2 + 4BD2 ----------- (1) Consider ΔABC AD2 = AB2 + BD2 [Pythagoras theorem] ----------- (2) Subtracting equation (2) from (1), we get ⇒ AC2 - AD2 = 3BD2 ⇒ AC2 - AD2 = 3CD2 [ Since BD = CD] ⇒ AC2 = AD2 + 3CD2 Hence proved.

Answer 2

using by 2 times pythagoras theoram prov it