Question

Answer it plz

(a + b + c)^2 = ?
(a + b)^2 = ?
( a - b)^2 = ?
(a + b)(a - b) = ?

Answer 1

Heya !!!

1. (a+b+c)^2 = a2 + b2 + c2 + 2ab + 2bc + 2ca

2. (a+b)^2 = a2 + b2 + 2ab

3. (a-b)^2 = a2 + b2 -2ab

4. (a+b)(a-b) = a2 - b2

Thanks...

Answer 2

$\large{\sf{\underline {\underline {Question:}}}}$


Write Formulas For :-

1. ( a + b + c )² = ?
2. ( a + b )² = ?
3. ( a - b )² = ?
4. ( a + b )( a - b ) = ?


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$\large {\sf{\underline {\underline {Answer:}}}}$


1. a² + b² + c² + 2ab + 2bc + 2ca
2. a² + 2ab + b²
3. a² - 2ab + b²
4. a² - b²


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$\huge \pink{ \mid \underline{ \overline{ \sf Brainly \: Solution : }} \mid}$


$\sf1. \: (a + b + c) {}^{2} \\ \ \\ \sf \to (a + b + c)(a + b + c ) \\ \\ \sf \to a {}^{2} + ab + ac + ba + {b}^{2} + bc + ca + cb + c {}^{2} \\ \\ \to \sf a {}^{2} + b {}^{2} + c {}^{2} + 2ab + 2bc + 2ca \\ \\ - - - - - - - - - - - - - - - - - - - - \\ \\ \sf 2. \:( a + b) {}^{2} \\ \\ \sf \to (a + b)(a + b) \\ \\ \to \sf {a}^{2} + ab + ba + {b}^{2} \\ \\ \to \sf a {}^{2} + 2ab + b {}^{2} \\ \\ - - - - - - - - - - - - - - - - - - - - \\ \\ \sf2. \: (a - b) {}^{2} \\ \\ \sf \to (a - b)(a - b) \\ \\ \to \sf a {}^{2} - ab - ba + {b}^{2} \\ \\ \sf \to a {}^{2} - 2ab + b {}^{2} \\ \\ - - - - - - - - - - - - - - - - - - - - - \\ \\ \sf 4. \: (a + b)(a - b) \\ \\ \sf \to {a}^{2} + \cancel{ ab} - \cancel{ ba} - b {}^{2} \\ \sf \to a {}^{2} - {b}^{2} \\ \\ - - - - - - - - - - - - - - - - - - - -$



✔✔ Hence, it is proved ✅✅.



$\huge \green{ \boxed{ \boxed{ \mathscr{THANKS}}}}$


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