Question

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Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

Your answer :-

Given:

OC = OA = OB = 5 cm ( Radius )

And

AB = BC = 2√5cm

OB and AC intersect at " D " .

Here In quadrilateral OABC , OA = OC and AB = BC , So OABC is a kite and we know in kite diagonals are perpendicular and one diagonal bisect other , So

∠ ADO = ∠ ADB = 90°

And

AD = CD = x

So,

AC = AD + CD = x + x = 2x

And Let OD = y , So , BD = 5 - y

now we apply Pythagoras theorem in triangle AOD

OD^2 + AD^2 = OA^2 , substitute all the values we get ,

y^2 + x^2 = 5^2

y^2 + x^2 = 25

y^2 = 25 - x^2 --- (1)

we apply Pythagoras theorem in triangle ABD

BD^2 + AD^2 = BA^2 , substitute all the values we get ,

( 5- y )^2 + x^2 = ( 2√5 )^2

25 + y^2 - 10 y + x^2 = 20

y^2 = 10y - x^2 - 5

Now substitute value from equation ( 1 )

25 - x^2 = 10y - x^2 - 5

10y = 30

y = 3

hence substitute this value in equation ( 1 ) we get

32 = 25 - x^2

x^2 = 25 - 9

x^2 = 16

x=√16

x = 4

AC = 2 ( 4) = 8 cm

Step-by-step explanation:

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