Question

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Answer 1

Answer:

3y-5-7x+5=180

3y-7x=180----------1

4y+20-4x=180

4y-4x=160

dividing each term by 4

y-x=40

y=40+x-------------2

putting 1 in2

3(40+x)-7x=180

120+3x-7x=180

-4x=60

x= -15

y=40-15

=25

so,

A=4*25 +20

=120

B=3*25-5

=70

C=-4*-15

=60

D=-7*-15+5

=110

hope it is right

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Answer 2

We know that the given figure is cyclic quadrilateral

So,

-4x + 4y +20 = 180°

=>y-x=40° _____(1)

and,

3y-5+(-7x+5) = 180°

=>3y-5-7x+5= 180°

=>3y-7x=180° _____(2)

Soving (1) and (2) we will get

by elimination method

(1) ×3 and(2) ×1

4x=-60°

=>x= -15°

y=25°

Now, the angle A, B, C and D are 120°, 70°, 60° and 110° Respectively.

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