Question

answer it plz plz soon
​

Answer 1

Step-by-step explanation:

ANSWER

asecθ+btanθ=1,asecθ−btanθ=5

cosθ

a+bsinθ

=1

a+bsinθ=cosθ.....(i)

cosθ

a−bsinθ

=5

a−bsinθ=5cosθ.......(ii)

addingequation(i)and(ii)

a+bsinθ=cosθ

a−bsinθ=5cosθ

2a=6cosθ

a=3coθ,a

2

=qcos

2

θ

puttingthevalueobtained(ii)

3cosθ−bsinθ=5cosθ

−2cosθ=bsinθ

−2cotθ=b,b

2

=4cot

2

θ

thena

2

(b

2

+4)=9cos

2

θ[4(1+cot

2

θ)]

=36cos

2

θ.cosec

2

θ

=36(

sinθ

cosθ

)

2

=36×cot

2

θ[⋅.⋅cot

2

θ=

4

b

2

]

=

4

36

b

2

9b

2

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Answer 2

Answer:

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