Question

answer it plz q 6 n 7 only

Answer 1

6. Let 3 consecutive integer be= X,X+1,X+2
Sum=51
A/Q
x+x+1+x+2=51
3x+3=51
3x=51-3
3x=48
x=48/3
x=16
3 consecutive integer
=16
16+1=17
16+2=18

7. Let First consecutive multiple=x

Multiple of 8 is when when we add 8 to a multiple to get another multiple of 8

Let consecutive multiples=x,x+8,x+8+8
Sum=888

A/Q
x+x+8+x+8+8=888
3x+24=888
3x=888-24
3x=864
x=864/3
x=288

First multiple=288
second multiple=288+8=296
Third multiple=288+8+8=304

Thanks

Answer 2

HERE IS YOUR ANSWER MATE:
first picture of 6th question

now question number 7 ;
Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

please please Mark as brainliest