Question

Answer it Question no 21

This question belongs to quadratic equation

Fake answer will be reported

50 points

Answer 1

Hey!!!!...here is ur answer

(2x/x-4)+(2x-5/x-3)=25/3

2x (x-3)+(x-4)(2x-5)/(x-4)(x-3)=25/3

[2x^2-6x+2x^2-13x+20]/x^2-7x+12=25/3

4x^2-19x+20/x^2-7x+12=25/3

12x^2-57x+60=25x^2-175x+300

13x^2-118x+240=0

hope it will help you ☺

Answer 2

Hello here ....☺
$we \: \: have \: \frac{2x}{x - 4} + \frac{2x - 5}{x - 3} = \frac{25}{3} \\ \\ = > \frac{2x(x - 3) + (2x - 5)(x - 4)}{(x - 4)(x - 3)} = \frac{25}{3} \\ \\ = > \frac{2 {x}^{2} - 6x + 2 {x}^{2} - 13x + 20}{ {x}^{2} - 7x + 12 } = \frac{25}{3} \\ \\ = > \frac{4 {x}^{2} - 19x + 20}{ {x}^{2} - 7x + 12 } = \frac{25}{3} \\ \\ = > 3(4 {x}^{2} - 19x + 20) = 25( {x}^{2} - 7x + 12) \\ \\ = > 1 {2x}^{2} - 57x + 60 = 25 {x}^{2} - 175x + 300 \\ \\ = > 13 {x}^{2} - 118x - 240 = 0 \\ \\ hence \: \: a = 13 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: b = - 118 \\ \: \: \: \: \: \: \: \: \: \: \: \: c = - 240$
Using quadratic formula find the Root



Hope this helps you...<<☺>>