Question

answer It quick please it's very important ​

Answer 1

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⋗ Answer :

$\huge{ \boxed{ \bold80}}$

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⋗ Given question :

$\sf(({\dfrac{1}{3})}^{-2} -({\dfrac{1}{2})}^{ - 2}) \div({\dfrac{1}{4})}^{2}$

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⋗ Solution :

$\implies \sf(({\dfrac{1}{3})}^{-2} -({\dfrac{1}{2})}^{ - 2}) \div({\dfrac{1}{4})}^{2}$

$\implies \sf({(3)}^{2} -({2)}^{2}) \times{(4)}^{2}$

$\implies \sf(9 - 4) \times16$

$\implies \sf5 \times16$

$\large \red{\bigstar} \implies { \underline{ \boxed{ \bold80}}}$

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⋗ formulas :

$\sf{(\dfrac{a}{b})}^{ -x} ={(\dfrac{b}{a})}^{ x}$

$\sf{x}^{0} =1\:(x\not=0)$

$\sf{{a}^{x}\times{a}^{y}={a}^{x + y} }$

$\sf{{a}^{x}\div{a}^{y}={a}^{x - y} }$

$\sf{{(a}^{x})}^{y} ={a}^{xy}$

$\sf{a}^{n} + {b}^{n} ={(a + b)}^{n}$

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