Question

answer it with details...​

Answer 1

Answer:

option d is incorrect if value of n increase so energy decrease but here - sign so basically energy increase and energy is invertionaly propotional to the stability so for smallest orbit electron bound tightly in smaal allow orbit

Answer 2

D option is the answer to this question.

This energy will be max for n = 1 so in smallest orbit it will be tightly bound not loosely.