Math, asked by ankit281020045665, 1 year ago

answer it with explanation​

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Answered by Anjaligiri
1

i)RHS=(secθ−tanθ)2

=(1cosθ−sinθcosθ)2

=(1−sinθcosθ)2

=(1−sinθ)2cos2θ

=(1cosθ-sinθcosθ)2

=(1-sinθcosθ)2

=(1-sinθ)2cos2θ

=(1−sinθ)2(1−sin2θ)

=(1−sinθ)(1−sinθ)(1+sinθ)(1−sinθ)

=(1-sinθ)2(1-sin2θ)

=(1-sinθ)(1-sinθ)(1+sinθ)(1-sinθ) 

=(1−sinθ)(1+sinθ)

 

∴RHS=LHS

Answered by anshiarya750
0

hope it will help you...

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