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l is parallel to m ,so co interior angles will be supplementary.
now , (angle 1 +angle 2 )+(angle 3+ angle 4 )=180 ....eq1
angle1 =angle 2 (given )
angle 3=angle 4( given as it is bisected)
putting these in eq 1
2(angle 1)+2(angle 3)=180
so angle 1 +angle 2=90
now , angle 1 +angle2 +x =180
x =180-90
x=90
similarly ,angle 5 +angle 7 +y =180 (y vertically opp angle )
y =180-90
y=90
now , (angle 1 +angle 2 )+(angle 3+ angle 4 )=180 ....eq1
angle1 =angle 2 (given )
angle 3=angle 4( given as it is bisected)
putting these in eq 1
2(angle 1)+2(angle 3)=180
so angle 1 +angle 2=90
now , angle 1 +angle2 +x =180
x =180-90
x=90
similarly ,angle 5 +angle 7 +y =180 (y vertically opp angle )
y =180-90
y=90
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