Question

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multiply (2x²-5x+4)by x²+7x-8 ?
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Answer 1

Answer:

Hey!!!

2x⁴+9x³–47x²+68x–32

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Answer 2

Answer:

2x^4 + 9x^3 - 47x^2 + 68x - 32

Step-by-step explanation:

(2x^2 - 5x + 4) x (x^2 + 7x - 8)

Distribute -

2  ( ^2  + 7 − 8 ) * x^2 - 5x(x^2 + 7x - 8) + 4(x^2+7x-8)

Then multiply them -

2x^4 + 14x^3 - 16x^2 - 5x^3 - 35x^2 + 40x + 4x^2 + 28x - 32

Now, we have to combine all the like terms.

(1) 2x^4 + 14x^3 - 16x^2 - 5x^3 - 35x^2 + 40x + 4x^2 + 28x - 32

        = 2x^4 + 9x^3 - 16x^2 - 35x^2 + 40x + 4x^2 + 28x - 32

(2) 2x^4 + 9x^3 - 16x^2 - 35x^2 + 40x + 4x^2 + 28x - 32

        = 2x^4 + 9x^3 - 47x^2 + 40x + 28x - 32

(3) 2x^4 + 9x^3 - 47x^2 + 40x + 28x - 32

         = 2x^4 + 9x^3 - 47x^2 + 68x - 32

Therefore, the solution is 2x^4 + 9x^3 - 47x^2 + 68x - 32

Hope it helps!

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