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x²-(√3+1)x+√3=0
x²-x-√3x+√3=0
x(x-1)-√3 (x-1)=0
x-√3(x-1)=0
hence.x=1 or √3
x²-x-√3x+√3=0
x(x-1)-√3 (x-1)=0
x-√3(x-1)=0
hence.x=1 or √3
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4
x² - (√3 + 1) x +√3 = 0
x² - √3x - x + √3 = 0
x(x - √3) -1(x - √3) = 0
(x - √3) (x -1) = 0
x = √3 or x = 1
x² - √3x - x + √3 = 0
x(x - √3) -1(x - √3) = 0
(x - √3) (x -1) = 0
x = √3 or x = 1
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