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Answer 1

Answer:

Given AC = 84 cm, DL = 16.5 cm and BM = 12 cm We know that area of triangle = ½ x base x height Area of triangle ADC = ½ (AC x DL) = ½ (84 x 16.5) = 693 cm2 Area of triangle ABC = ½ (AC x BM) = ½ (84 x 12) = 504 cm2 Hence, Area of quadrilateral ABCD = Area of ADC + Area of ABC = (693 + 504) cm2  = 1197 cm2Read more on Sarthaks.com - https://www.sarthaks.com/690502/in-fig-abcd-is-a-quadrilateral-in-which-diagonal-ac-84-cm-dlac-bmac-dl-16-5-cm-and-bm-12-cm