Math, asked by aqimshaik, 16 days ago

answer!
maths
chapter name : polynomial​

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Answers

Answered by salmasiddiqui772
1

I hope this pic helpful for you

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Answered by raibanaaz12345
2

Answer:

a) Here, p(x)=3x.

In order to find zero of p(x), we equate p(x) to 0,

i.e p(x)=0.

⇒3x=0⇒x=0.

∴ 0 is the zero of p(x).

b) x

2

+5x+6=0

x

2

+2x+3x+6=0

x(x+2)+3(x+3)=0

(x+2)(x+3)=0

x=−2,−3

c) p(x)=(x+2)(x+3) This is a quadratic polynomial . It has two zeroes .

Let P(x)=0

⇒(x+2)(x+3)=0

⇒x+2=0,x+3=0

⇒x=−2,x=−3

∴ The zeroes of the polynomial are

−2 and −3.

d) P(x)=x

4

−16

Let ,

P(x)=0

⇒x

4

−16=0

⇒(x

2

)

2

−4

2

=0

⇒(x

2

−4)(x

2

+4)=0

⇒(x+2)(x−2)(x

2

+4)=0

⇒x+2=0,x−2=0,x

2

+4=0

⇒x=−2,x=2,x=±

−4

∴ The zeroes of the polynomial are

−2,2 and ±

−4

PLS mrk as brainliest answer and follow

it takes too much time

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