Question

answer me 11 and 12 question I will ......mark as a brain list answer and follow up ...
Fastttttt.!!!!​

Answer 1

Connect two in parallel and the third one in series to get 9 ohms

Connect two in series and the third in parallel to get 4 ohms

Answer 2

for one bulb:

power P=10W and potential difference= 220V

using the relation for R, we have

R=V^2/P =(220)^2/10 = 4840ohm

let the total number of bulbs be X

given tht :

current = i=5A and pd =220V

according to ohm's law, V=IR

so, R=V/I =220/5 = 44ohm

Now, for X number of bulbs of resistance of resistance connected in parallel is 44ohm

1/44 = 1/4840 + 1/4840 + 1/4840...to X times

1/44 = X/4840

here, X= 4840/44 =110

therefore, 110bulbs of 4840ohm are requires to draw the given amount of current!!!!!

plz mark it as brain list!

and soory 11 ka answer bht bda hai type krna mushkl h