answer me 21st question pls
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we have two zeroes here 1st 2/√3 and 2nd 2√3
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Hello dear friend,
So u can get the answer in the following way:
√3x^2 - 8x + 4√3
here it cann be factorised as : √3x^2 -6x - 2x+ 4√3
so it becomes : √3x ( x - 2√3 ) -2x (x - 2√3 )
so u can get : (√3x -2x ) (x - 2√3 )
so the zeroes u get are : x = 2 / √3 , or x = 2√3
Hope this helps !! thankyou & goodluck !!
So u can get the answer in the following way:
√3x^2 - 8x + 4√3
here it cann be factorised as : √3x^2 -6x - 2x+ 4√3
so it becomes : √3x ( x - 2√3 ) -2x (x - 2√3 )
so u can get : (√3x -2x ) (x - 2√3 )
so the zeroes u get are : x = 2 / √3 , or x = 2√3
Hope this helps !! thankyou & goodluck !!
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