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Given that
hight of cylinder h = 180cm
radius of cylinder r = 60cm
and,
Two parts of toys
readius of hemisphere r = 60cm
readius of cone r = 60cm
height of cone h = 120cm
volume of toy= volume of hemisphere + volume of cone
= 4/3πr³+1/3πr²h
= 4/3×22/7×(60)³+ 1/3×22/7×(60)²×120
= 88/7×3 ×216000 + 22/3×7 ×3600×120
= 88/7 ×72000 + 22/7 ×1200×120
= 88×72000/7 + 22×144000/7
= 6336000/7 + 3168000/7
= 105000 + 452571.42 approx
= 557571.42 cm² approx
Volume of cylinder = πr²h
= 22/7 × (60)²×180
= 22×3600×180/7
= 79200×180/7
= 14256000 cm²
Volume of remaining water=volume of cylinder - volume of toy
= 14256000 - 557571.42
= 13698428.58 cm³ approx
Hence, the volume of remaining water is 13698428.58cm³
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