answer me fast guys
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hope it helps......hahahaha
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Step-by-step explanation:
Given that A.P consists of three terms.
Let it be a - d, a, a + d.
Now,
(1)
Sum of three terms is 15.
a - d + a + a + d = 15
=> 3a = 15
=> a = 5
(2)
Sum of their squares of extremes is 58.
(a - d)^2 + (a + d)^2 = 58
=> a^2 + d^2 = 29
=> d^2 = 4
=> d = 2, -2
When d = 2:
a - d = 3
a = 5
a + d = 7
When d = -2
a - d = 7
a = 5
a + d = 3
Therefore,
The three terms are 3,5,7..
Now,
We have to find sum of 50 terms:
Here,
n = 50, a = 3, d = 2.
sn = (n/2)[2a + (n - 1)d]
= (50/2)[6 + 49 * 2]
= 25[104]
= 2600.
Hope it helps!
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