Question

answer me fast I am getting late​

Answer 1

Answer:

1.$\sqrt{ {x}^{a - b} } \sqrt{ {x}^{b - c} } \sqrt{ {x}^{c - a} } = \sqrt{ {x}^{a - b + b - c + c - a} } = \sqrt{ {x}^{0} } = 1$

2.

${9}^{x + 2} = {9}^{x} + 240 \\ {9}^{x + 2} - {9}^{x} = 240 \\ {9}^{x} ( {9}^{2} - 1) = 240 \\ {9}^{x} = \frac{240}{80} = 3 \\ x = \frac{1}{2} \\ so \: \: now \\ \\ {8x}^{x} = (8 \times \frac{1}{2} ) {}^{1 \over2} = \sqrt{4} = 2$

3 .$\\\\since \: \: {y}^{0} = 1 \: \: \: \: for \:any \: \: y \neq0 \\ so \: \: x = 0$