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we have given that parrlogram diagonal intersect at 90 degree
so diagonal bisecte in equal when it 6 so it bisct 3 cm given and 8 bisect given 4 cm
now we use pyathagoras theorm in question
in triangle AOB
H^2=B^2+P^2
H^2=3^2+4^2
H^2 =9+16
H^2=25
H=5
SO SIDE IS 5 CM EACH
so diagonal bisecte in equal when it 6 so it bisct 3 cm given and 8 bisect given 4 cm
now we use pyathagoras theorm in question
in triangle AOB
H^2=B^2+P^2
H^2=3^2+4^2
H^2 =9+16
H^2=25
H=5
SO SIDE IS 5 CM EACH
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if diagonal are intersecting each other at right angle, measure of length of both diagonal is different then that parallelogram becomes rhombus.
if parallelogram is rhombus then the diagonal will bisect each other.
if parallelogram is rhombus then the diagonal will bisect each other.
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