Question

Answer me fast I want all three questions.​

Answer 1

10)

Red marbles = 3

Blue marbles = 2

Total marbles = 5

$p(e) = \frac{no \: of \: favourable \: outcomes}{total \: no \: of \: outcomes}$

$p(blue) = \frac{2}{5}$

11)

Total electric bulbs = 600

Defective bubs = 12

Non defective bulbs = 588

$p(non \: defective) = \frac{588}{600} = \frac{49}{50}$

12)

when a die is thrown

1, 2, 3, 4, 5, 6

$(i) \: p(even) = \frac{3}{6} = \frac{1}{2}$

$(ii) \: p(multiple \: of \: 3) = \frac{2}{6} = \frac{1}{3}$

$(iii) \: p(3 \: or \: 4) = \frac{2}{6} = \frac{1}{3}$

$(iv) \: p(odd) = \frac{3}{6} = \frac{1}{2}$

$(v) \: p(between \: 3 \: and \: 6) = \frac{2}{6} = \frac{1}{3}$

Please mark me great if my answers are correct

Answer 2

Answer:

Red marbles = 3

Blue marbles = 2

Total marbles = 5

p(e) = \frac{no \: of \: favourable \: outcomes}{total \: no \: of \: outcomes}p(e)=

totalnoofoutcomes

nooffavourableoutcomes

p(blue) = \frac{2}{5}p(blue)= 52

11)

Total electric bulbs = 600

Defective bubs = 12

Non defective bulbs = 588

p(non \: defective) = \frac{588}{600} = \frac{49}{50}p(nondefective)= 600588 = 5049

12)when a die is thrown

1, 2, 3, 4, 5, 6

(i) \: p(even) = \frac{3}{6} = \frac{1}{2}(i)p(even)= 63 = 21

(ii) \: p(multiple \: of \: 3) = \frac{2}{6} = \frac{1}{3}(ii)p(multipleof3)= 62= 31

(iii) \: p(3 \: or \: 4) = \frac{2}{6} = \frac{1}{3}(iii)p(3or4)= 62 = 31

(iv) \: p(odd) = \frac{3}{6} = \frac{1}{2}(iv)p(odd)= 63 = 21

(v) \: p(between \: 3 \: and \: 6) = \frac{2}{6} = \frac{1}{3}(v)p(between3and6)= 62 = 31