Chemistry, asked by dimple658, 7 months ago

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Answered by yashkm111204
1

Answer:

Atomic Number of Beryllium = Z= 4

Hence, Number of Electron in Be -atom (in neutral state) = 4

In case Be+3 ion , Number of Electron = 1 (electron in the K -shell)

In this case, Be+3 ion will behave as Hydrogen-like-entity . Also, electron in N-shell means that it is in

excited state. Hence, we can apply Bohr’s theory in calculating energy of an electron in a particular orbit :—

Potential Energy of the electron in the N-shell of Be+3 ion = -27.2 eV/ion .

Explanation:

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