Question

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Answer 1

Answer

Given that x3 – 2x2 – x + 2

Grouping the 1st and 3nd terms together and the 2nd and 4th term together:

= x(x2 – 1) – 2(x2 – 1)

x3 – 2x2 – x + 2 = (x2 – 1) (x – 2)

Using the identity: a2 − b2 = (a + b) (a- b)

∴ (x2 – 1) = (x + 1)(x – 1)

= (x – 1) (x + 1) (x- 2)

∴ answer is (x – 1) (x + 1) (x- 2)

Itz Harsh

Answer 2

Step-by-step explanation:

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let x-1=0

x=1

put value of x in the equation,we get

(1)^3-2(1)^2-(1)+2

1-2-1+2

3-3

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