Question

answer me fast its urgent ​

Answer 1

Given :-

p(x) = x^6+5x⁴-6x³+2

q(y)=6y^5+4y⁴+3y³+1

To find:-

[p(2)-q(-2)] /3

therefore,p(2)=2^6+5×2⁴-6×2³+2

=64+5×16-6×8+2

=64+80-48+2

=98

And,q(-2)= 6×(-2)^5+4×(-2)⁴+3×(-2)³+1

=6×(-32)+4×(-16)+3×(-8)+1

=(-279)

Hence ,{p(2)-q(-2)}/3

={98-(-279)}÷3

=(98+279)÷3

=>377/3=125.6667

Hope it's right and helps you !!!!