Question

answer me fast plz need help .. take a short from ur copoy and send me i need the full steps​

Answer 1

Answer:

I hope it will help you....

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Answer 2

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$\bf{(e) \: 2x - \frac{3}{x} = 5} \\ \bf{or, \: \frac{2 {x}^{2} - 3 }{x} = 5} \\ \bf{or, \: 2 {x}^{2} - 3 = 5x } \\ \bf{or, \: 2 {x}^{2} - 5x - 3 = 0} \\ \bf{or ,\: 2 {x}^{2} - (6 - 1)x - 3 = 0 } \\ \bf{or ,\: 2 {x}^{2} - 6x + x - 3 = 0 } \\ \bf{or, \: 2x(x - 3) + 1(x - 3) = 0} \\ \bf{or ,\: (x - 3)(2x + 1) = 0} \\ \\ \bf{ \underline{Either}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{ \underline{Or}} \\ \bf{x - 3 = 0} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:2x + 1 = 0 \\ \bf{or ,\: x = 3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or ,\: 2x = - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{or, \: x = \frac{ - 1}{2} }$

$\bf{(e) \: 2x - \frac{3}{x} = 5} \\ \bf{or, \: \frac{2 {x}^{2} - 3 }{x} = 5} \\ \bf{or, \: 2 {x}^{2} - 3 = 5x } \\ \bf{or, \: 2 {x}^{2} - 5x - 3 = 0} \\ \bf{or ,\: 2 {x}^{2} - (6 - 1)x - 3 = 0 } \\ \bf{or ,\: 2 {x}^{2} - 6x + x - 3 = 0 } \\ \bf{or, \: 2x(x - 3) + 1(x - 3) = 0} \\ \bf{or ,\: (x - 3)(2x + 1) = 0} \\ \\ \bf{ \underline{Either}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{ \underline{Or}} \\ \bf{x - 3 = 0} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:2x + 1 = 0 \\ \bf{or ,\: x = 3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or ,\: 2x = - 1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{or, \: x = \frac{ - 1}{2} }$

$\bf{(h) \: \frac{2x}{5 - 3x} = \frac{5 + 3x}{8x} } \\ \bf{or , \: 16 {x}^{2} = (5 + 3x)(5 - 3x) } \\ \bf{or,\: 16 {x}^{2} = {5}^{2} - {(3x)}^{2} } \\ \bf{or ,\: 16 {x}^{2} = 25 - 9 {x}^{2} } \\ \bf{or, \: 16 {x^2 } + 9 {x}^{2} } = 25 \\ \bf{or, \: 25 {x}^{2} = 25} \\ \bf{or ,\: {x}^{2} = \frac{25}{25} } \\ \bf{or, \: {x}^{2} = 1} \\ \bf{or ,\: x = ±1}$