Physics, asked by Anonymous, 6 months ago

Answer me fast plz.....solve it....​

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Answered by Anonymous
11

Let the mass and radius of Mars be m and r respectively.

According to the Question,

  • Mass of Earth would be : 9m
  • Radius of Earth would be : 2r
  • Escape Velocity of Earth is 11.2 Km/h

A generalized expression for escape velocity is,

 \sf \: v =   \sqrt{\dfrac{GM}{R} }

For Mars,

 \sf \: v_m = v =  \sqrt{ \dfrac{Gm}{r} }

For Earth,

 \sf \: 11.2 =  \sqrt{ \dfrac{9Gm}{2r} }

Dividing both the equations, we get :

 \sf \:  \dfrac{v}{11.2}  =  \frac{  \sqrt{ \dfrac{Gm}{r} }}{  \sqrt{ \dfrac{9Gm}{2r} }} \\  \\  \implies \sf \:  \dfrac{v}{11.2}  =  \sqrt{ \dfrac{2}{9} }  \\  \\  \implies \sf \: v = 11.2 \times  \sqrt{0.22}  \\  \\  \implies \sf \: v = 0.46 \times 11.2 \\  \\  \implies \boxed{ \boxed{ \sf v_m \:  = 5.25 \: kmh {}^{ - 1} }}

Escape Velocity on Mars is 5.3 Km/h

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