Math, asked by Raviraj95, 1 year ago

answer me fast plzzzzzzzz!

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Answers

Answered by BrainlyHulk
0
#include<iostream.h>
void main()
{
char A[] ;
cin>> A ;
for ( int I = 0 ; I < N ; I++ )
{
if ( A[I] == 'A' || A[I] == 'a' || A[I] == 'E' || A[I] == 'e' || A[I] == 'i' || A[I] == 'I' || A[I] == 'O' || A[I] == 'o' || A[I] == 'U' || A[I] == 'u' )
{
cout << A[I] ;
}
}
return 0 ;
}

Raviraj95: i have to do it in java
BrainlyHulk: i dont know java
Raviraj95: ok
BrainlyHulk: you may have posted in question that you wamted java
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