Question

answer me from attach ment ​

Answer 1

QuEsTiOn :-

The sum of three consecutive multiples of 8 is equal to eight times the sum of the first to

consecutive multiples of 6. Find each of the three multiples of 8.

Answer :-

The consecutive multiples of 8 are 40, 48 and 56

Given:

Sum of three consecutive multiples of 8 is equal to eight times the sum of the first two consecutive multiples of 6.

To find:

The three multiples of 8.

SoLuTioN :-

Consider ,

The three multiples of 8 be x, x + 8 and x + 16

The first two multiples of 6 are 6 and 12

Now , as per the Question :-

x + x + 8 + x + 16 = 8 ( 6 + 12)

3x + 24 = 144

3x = 144 - 24

↠ 3x = 120

↠ x = 120/3

↠ x = 40

First multiple = 40

Other multiples:

↠ x + 8 = 40 + 8 = 48

↠ x + 16 = 40 + 16 = 56

Hence ,

The required consecutive multiples of 8 are 40, 48 and 56.

Answer 2

☆ Question ☆

The sum of three consecutive multiples of 8 is equal to eight times the sum of the first two consecutive multiple of 6. Find each of three multiples of 8.

☆ Solution ☆

Given

• The sum of three consecutive multiples of 8 is equal to eight times the sum of the first two consecutive multiple of 6.

To find

• Each of three multiples of 8.

Step-by-Step-Explaination

Let,

The three multiples of 8 be x, x + 8 and x + 16

The first two multiples of 6 are 6 and 12

According to the question

x + x + 8 + x + 16 = 8 ( 6 + 12 )

3x + 24 = 144

3x = 144 - 24

=> 3x = 120

=> x = $\frac{120}{3}$

=> x = 40

First multiple = 40

Other multiple

x + 8 = 40 + 8 = 48

x + 16 = 40 + 16 = 56

Therefore, the consecutive multiples of 8 are 40, 48 and 56.