Question

answer me guy
good afternoon

Answer 1

Answer:

loge(x+1)+1/(x+1)

Step-by-step explanation:

let I be the integration,

I=x/(x+1)^2

put,x=x+1-1

I=(x+1)-1/(x+1)^2

I=1/(x+1)-1/(x+1)^2

I=loge(x+1)+1/(x+1)

i hope it will help,mark me as a brainliest:)

Answer 2

Here is ur answer...

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