Question

answer me. I dekhte hi kiska dimag hai​

Answer 1

L = 1

Now here L + T = O

So O >T

And Carry( x) + L + T = LM

x + L + T = 10 L + M

x - 9 L + T = M

L = 1

x- 9 + T = M

x- 9 = M - T

T = M - x+ 9

And

O + E = xF

O + E = 10 x + F

10 x + F - E = 0

Now O>T

10 x + F - E > M - x + 9

11 x + F - E >M + 9

Now here

O + E = x + f ( x is carry)

As we know max digit is 9

So 9+9 = 18

That means only 1 is possible as carry which is x

So

11x + F - E >M + 9

11 + F - E >M + 9

2 >M + E - F

O = 3 not possible

because T should be 2 then

L + T + x = 1 + T + x should be 2 digit

T + x >= 9

x= 1

T >= 8

So take 8

L = 1

O = 9

T = 8

T can't be 9 as O >T so not possible

So T = 8 , O= 9 ,L = 1

L + T + 1 = LM

1 + 8 + 1 =10

M= 0

and E can be any digit except 0

So

LMFO IS

1 0 F( 0,.....8) 9

10 0 9

10 19

1029

1039

1049

1059

1069

1079

1089

✌✌✌Dr.Dhruv✌✌✌✌✌