Question

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Answer 1

Step-by-step explanation:

Let the two adjacent sides of the parallelogram be a = 51 cm, b = 37 cm 

Let the length of diagonal be c = 20 cm 

These two sides and the diagonal forms a triangle semi perimeter,

s = (a + b + c) / 2 s = (51 + 37 + 20)/2 = 54 cm 

By Heron's formula, we have area of triangle, 

Δ = √s(s - a)(s - b)(s - c) 

= √[54(54 - 51)(54 - 37)(54 - 20) 

= √54 x 3 x 17 x 34 = 306 sq cm 

Area of parallelogram = 2 x area of triangle = 2 x 306 = 612 sq cm

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