Question

answer me in copy please send me the answer please please please please please please please please please please please please please please ​

Answer 1

$\huge\rm{GIVEN}$

• $\rm{First\:Side\:of\:triangular\:Field = 120m}$

• $\rm{Second\:of\:Triangular\:Field = 80m.}$

• $\rm{Third\:Side\:of\:Triangular\:Field = 60m.}$

• There is a Gate of width 10m.

$\huge\rm\blue{To\:Find}$

$\rm{The length of wire needed for fencing.}$

• The Cost of fencing at the rate of 6 Per meter.

• The Area of Triangular field.

Perimeter of Triangle = Length of wire needed for fencing.

Atq.

• $\rm{Actual\:first\:Sides\:of\:triangle = 120-10 = 110m}$

• $\rm{Actual\:Second\:side\:of \:Triangle = 80-10= 70m}$

• $\rm{Actual\:Third\:side\:of\:triangle = 60- 10 = 50m}$

Now,

➡️Perimeter of triangle = (a+b+c)

➡️Perimeter of triangle = 110+70+50 = 230m.

Hence, The length of wire needed for fencing is 230×2 = 460m.

Now,

➡️Cost of fencing at the rate of 6 per metre= 6

➡️Cost of fencing 460m = 460×6 =.2760rupees.

Now,

$\implies\tt{Area\:of\:triangle=\sqrt{(s)(s-a)(s-b)(s-c)}}$

Where,

$\rm{S= \dfrac{Perimeter}{2}}$

We will take original Sides of traingle

$\rm{S=\dfrac{260}{2}}$

$\rm{S= 130}$

$\implies\tt{Area\:of\:\triangle=\sqrt{(130)(130-120)(130-80)(130-70)}}$

$\implies\tt{Area\:of\:\triangle=\sqrt{130\times{10}\times{50}\times{60}}}$

$\implies\tt{Area\:of\:\triangle=\sqrt{3900000}}$

$\implies\tt{Area\:of\:\triangle=1974.8m}$