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Remainder theory
x+1=0
x=1
f(x) = x^3+3x^2+3x+1
f(1) = (1)^3 + 3 (1) ^2 + 3 (1) + 1
= 1 + 3 + 3 + 1
=8
so x+1 is not a factor of this equation.
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