:)answer me please :)
Attachments:
Answers
Answered by
0
we know that in a rhombus all the sides are equal so angles opposite to sides are also equal
in triangle cdb angleCBD = angleCDB
and sum of opposite angles of a quadrilateral is equal to 180° so 70 + ANGLECBD = 180
ANGLEbcd = 110°
now coming to triangle bcd sum of all angle = 180°
2x+110 = 180
x = 35°°
hence angleCDB(x) = 35°
in triangle cdb angleCBD = angleCDB
and sum of opposite angles of a quadrilateral is equal to 180° so 70 + ANGLECBD = 180
ANGLEbcd = 110°
now coming to triangle bcd sum of all angle = 180°
2x+110 = 180
x = 35°°
hence angleCDB(x) = 35°
vedha03:
is answer correct
Similar questions