Question

answer me please all

Answer 1

c is the answer for your question

Answer 2

Hi there!
Here's the answer:

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If A is x% more than B, then B is less than that of A by

$(\frac{x}{x+100} × 100)\%$

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EXPLANATION:

$A = B + \frac{x}{100}B = (\frac{100+x}{100})B$

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$A - B = (\frac{100+x}{100}B) - B$

=$(\frac{100+x}{100} -1)B = \frac{x}{100}B$

So, $\frac{A-B}{A} = \frac{\frac{x}{100}B}{\frac{100+x}{100}B}$

=> $\frac{A-B}{A} = \frac{x}{100+x}$

=> $A-B = (\frac{x}{100+x}×100)\%\: of\: A$

Therefore,

B is less than that of A by

$(\frac{x}{100+x}×100)\%$

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SOLUTION :

Given,
A> B by 30%
B<A by ?%

Here,
x = 30

Substitute in formula

$(\frac{30}{100+30}×100)\%$

= $(\frac{30}{130}×100)\%$

= $(\frac{300}{13})\%$

= $(23\frac{1}{13})\%$

•°• This answer exists in $\underline{\underline{Option\: C}}$

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Hope it helps