Question

Answer me please friends​

Answer 1

${ \large{ \rm{ \red{ \underline{GivEn} \colon}} }}$

${ \large{ \sf{ \implies{3x - 5y = 4}}}}$

${ \large{ \sf{ \implies{9x - 2y = 7}}}}$

${ \large{ \rm{ \pink{ \underline{SoLutioN} \colon}}}}$

${ \large{ \sf{ \implies3(3x - 5y) = 3 \times 4}} \: \: { {\tt( \: multiply \: \: 3 \: \: on \: \: both \: \: side \: \: of \: \: first \: \: equation)}}}$

${ \large{ \sf{ \implies{9x - 15y = 12}}}} \: \: \: \: \: \: \: { \large\sf( \: first \: \: equation \: )}$

${ \large{ \sf{ \implies{9x - 2y = 7}}}} \: \: \: \: \: \: \: ({ \large \sf{ \: second \: \: equation}})$

${ \large{ \sf{ \implies{9x - 15y - (9x - 2y) = 12 - 7}}}}$

${ \large{ \sf {\implies{ \cancel{9x} - 15y - { \cancel{9x}} + 2y = 5}}}}$

${ \large{ \sf{ \implies{ - 13y = 5}}}}$

${ \large{ \sf{ \implies{y = \dfrac{ - 5}{13} }}}}$

${ \large{ \sf{ \implies{x = 4 + 5y \: ={ \bigg (} 4 + 5 \times \dfrac{ - 5}{13} { \bigg)}}}}}$

${ \large{ \bf{ \therefore \: \: {x = \dfrac{27}{13} \: \: \: and \: \: y = \dfrac{ - 5}{13} }}}}$