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Q 20)Initial speed of train A and B=72 km/h = 72*5/18 m/s =20 m/s
Acceleration of train B=1 m/s
Therefore displacement of the train in 50 s of acceleration=ut + 1/2at^2(Where u is initial velocity, t is total time and a is acceleration)
=(72*50 + 1/2*50*50*1)
=(3600 + 1250) m
=4850 m
The total length of the two trains = 400 m +400 m = 800 m
Therefore, the original distance between the two trains was (4850-800)m
=4050 m (Ans)
Q 21)Velocity of car = 18 m/s
Therefore velocity in km/h = 18*18/5 km/h
=64.8 km/h (Ans)
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