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Not sure..
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Sorry dr..
Which std??
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Given:-
∠PQR=∠PRQ
To Prove:-
∠PQS=∠PRT
Proof:-
Let us consider line segment ST at Q
∠PQR+∠PQS=180° –––(1)
[angles on same segment]
Similarly, Let us consider line segment ST at R
∠PRT+∠PRQ=180° –––(2)
[angles on same segment]
By comparing (1) and (2)
∠PQR+∠PQS=∠PRT+∠PRQ
∠PQR+∠PQS=∠PRT+∠PQR
[∠PQR=∠PRQ, Given]
∠PQS=∠PRT
Hence Proved
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