Question

answer me pls this queisn????????????????????????

Answer 1

hope it help you dear.....

Answer 2

QUESTION.

Resolve into partial fraction.


$\frac{1}{ {x}^{3} + 1 }$






Answer.


STEP 1


USING FORMULA


$( {x}^{3} + 1) = (x + 1)( {x}^{2} - x + 1)$




STEP 2



SET THE EQ IN VARIABLES


A, B, C



$\frac{1}{ {x}^{3} + 1} = \frac{a}{x + 1} + \frac{bx + c}{ {x}^{2} + x + 1}$


NOTE.

KINDLY LOOK IN ATTACHMENT FOR SOLUTION .




$a = \frac{1}{3}$



$b = \frac{ - 1}{3}$



$c = \frac{2}{3}$




so eq become

$\frac{1}{ {x}^{3} + 1} = \frac{ \frac{1}{3} }{x + 1} + \frac{ \frac{ - 1}{3} x + \frac{2}{3} }{ {x}^{2} + x + 1}$