answer me plse what is the value of k
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Hope this helps you :)
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a(n-1) = a + (n-2)d
k+9 = a + nd -2d
nd = k+9-a+2d ---(i)
a(n) = a + (n-1)d
2k-1 = a + nd - d
2k-1 = a + k+9-a+2d-d (using (i))
k = 10+d ----(ii)
a(n+1) = a + nd
2k + 1 = a + nd
2(10+d) = a + k + 9-a+2d
20+2d = k +9 +2d
k= 11
k+9 = a + nd -2d
nd = k+9-a+2d ---(i)
a(n) = a + (n-1)d
2k-1 = a + nd - d
2k-1 = a + k+9-a+2d-d (using (i))
k = 10+d ----(ii)
a(n+1) = a + nd
2k + 1 = a + nd
2(10+d) = a + k + 9-a+2d
20+2d = k +9 +2d
k= 11
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