Question

Answer me.......plsplspsls​

Answer 1

• ${a}^{m} . {a}^{n} \: = \: {a}^{mn}$

Addition if the number are in multiplication and subtract if numbers are in divisible.

Now.. the power are in multiply. So, they will add up.

=> ${a}^{m\:+\:n} \: = \: {a}^{mn}$

=> m + n = mn _______ (eq 1)

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• m(n - 2) + n(m - 2)

=> mn - 2m + mn - 2n

=> 2mn - 2m - 2n

=> 2mn - 2(m + n)

=> 2mn - 2(mn) [From (eq 1)]

=> 2mn - 2mn

=> 0

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m(n - 2) + n(m - 2) is 0

_________ [ ANSWER ]

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Answer 2

a^(m + n) = a^mn

So,

m + n = mn

Now;

m(n - 2) + n(m - 2)

mn - 2m + mn - 2n

2mn - 2m - 2n

2mn - 2(m + n)

2mn - 2(mn)

2mn - 2mn = 0